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By Connor Davidson | July 18th 2009 01:21 PM | Print | E-mail | Track Comments

In this short post I wish to explain how to solve simple quadratic equations with Trinomial factorisation


To solve a quadratic equation in this form there are two main methods you can use to solve these either trinomial (also known as quadratic) factorisation or the quadratic formula. In this article I will explain the factorisation method.

In maths it is always easier to use an example than to explain with words alone.


Ex1: Solve by factorisation x2 + 8x + 12 = 0



1.    Break into two brackets with an x in each:



> (x ) (x     )


2.    Find two numbers that add to give 8 and multiply to give 12. Then place in the other side of each bracket.   



> (x    6) (x    2)



3.    Put in the sign (+ of -) since the numbers are +ve use a plus sign.




> (x   +    6) (x   + 2)


4.    Multiply out to check:



  > (x   +    6) (x   + 2)


= x2 x 8x + 12


5.    Re write as:



> (x   +    6) =0


Or<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />



> (x   + 2) = 0


This gets more complicated when you use either –ve numbers or start with more than one x2. Here is a worked example:




Ex2: Solve by factorisation 3x2 + x – 4



>(3x   ) (x   )



> (2x 4) (x 1)



> (2x   +    4) (x    -   1)



 



 



 



<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /> 



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