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By Tommaso Dorigo | May 21st 2009 03:14 PM | 21 comments | Print | E-mail | Track Comments
About Tommaso

I am an experimental particle physicist working with the CMS experiment at CERN and the CDF experiment at Fermilab. In my spare time I play chess...

View Tommaso's Profile
Last Tuesday CDF announced their own discovery of the Omega_b baryon, a measurement which creates a controversy with the competing experiment at the Tevatron collider, DZERO. That is because DZERO had already claimed discovery for that particle, almost one year ago, and because the two measurements disagree wildly with each other. Just browse through my past few posts in this column and you will find all the information you need (how lazy can one be with links?).

I already discussed why the comparison of the two measurements shows that the one we have to abandon is DZERO's. Here, I will just conclude my test of the DZERO signal with pseudo-experiments -a technique I have already put at work in a previous post, where I showed that the claimed 5.4 standard deviations claimed by DZERO in their paper could not be more than 4.8 or 4.9.

Let us take the two measurements by CDF and DZERO at face value. DZERO claims that the mass is 6165 MeV, and assigns to that estimate a 10 MeV error from statistical sources, and a 13 MeV error from systematics. CDF claims that the mass is 6054.4 MeV, with a 6.8 MeV statistical and 0.9 MeV systematical uncertainty.

The first error in the two numbers above, "statistical", describes what is the constraining power of the amount of Omega_b candidates which was used for the measurement. It is a quite uncontroversial figure, which cannot be wrong under normal circumstances. The second error instead is an attempt to quantify how much the measurement conditions, the technique used, the peculiarities of the data, and other subtle effects may have impacted the determination of the mass, biasing it off its real value. Systematic uncertainties are typically hard to assess, and their proper handling shows the experience of the experimenter's hand.

The two mass measurements disagree by more than six standard deviations, but we can actually devise a means to determine how likely it is that one of them is right and the other is wrong. For, imagine that the CDF result is correct: you can now take the Omega_b mass as measured by CDF, the production rate as measured by CDF, and plug these numbers in a pseudo-experiment generation, asking the question of what could DZERO see in their data under such conditions.

The above recipe amounts to generating 79 events (plus or minus a few) by taking 5.99 of them from a Gaussian distribution, of width 34 MeV (DZERO's experimental mass resolution), and 73.01 from a flat background shape. After a suitable Poisson fluctuation, the resulting histogram can be fit "a' la DZERO". Under normal conditions, the fit will return what you have put in: a signal of about 6 events, sitting at 6054.4 MeV, give or take fifteen MeV or so.

Occasionally, though, those 6 events could be more, and they could conspire with a weird background fluctuation occurring at masses just above 6054 MeV, to create a signal which can be fit with a larger number of signal events, at a higher mass. Let me remind you that DZERO, in its mass distribution containing 79 events, fits 17.8 signal events. How often does that happen ?

Well, not quite often, indeed. In a hundred thousand pseudoexperiments, never does a 17.8 event signal appear at 6165 MeV or in its surroundings. The plot can be seen below.

dzero omega_b baryon CDF

In the graph, every black point is a pseudoexperiment. The x-axis shows the fitted mass, and the vertical axis describes the number of fitted signal events. As you see, there is a large blob of pseudoexperiments where the fit gives the correct answer: a mass close to the generated one (6054 MeV or so), and a signal of 6 events -sometimes fluctuating up, even significantly so. Again, note that at the mass where DZERO finds its Omega_b, there are no pseudoexperiments finding a sizable signal. Also note that the fact that six out of 79 events were generated at 6054 MeV does not imply that the fitter won't sometimes choose a different fluctuation happening elsewhere in the spectrum: that is the meaning of the black band running around, with a fitted number of signal events happening to be centered at about 6 events by pure chance (it is a feature due to the number of generated data in the fitted histogram and the width of the signal which is sought).

The machinery we have put together can be used to investigate a slightly modified version of the question we posed above; a much more interesting one, in fact.

The most likely source of the CDF/DZERO discrepancy lies, as is typically the case, in not-well-controlled systematical uncertainties by one of the two experiments. So, suppose we were to inflate the systematic uncertainty in the DZERO measurement with a factor K; K=1 would be the default measurement, while K=2 would mean that the mass systematic quoted by DZERO was underestimated by a factor two. Now, by inflating the systematics, we can actually perform what is called a "convolution" of the results of pseudoexperiments shown above, with the experimental mass resolution of DZERO.

What I am getting at is the following: if DZERO measures a mass value with a large enough error bar, it would end up agreeing with the more precise CDF result. How large has this error bar become ? By how much do we have to blow up the DZERO systematics ?

We can solve the problem by taking a Gaussian function centered at 6165 MeV, with a width equal to sqrt(10^2+K^2*13^2) MeV, and adding together the value of this function at all mass values corresponding to pseudoexperiments that returned a number of signal events above 17.8. This number, divided by the total number of generated pseudoexperiments, is an estimate of the probability that DZERO observed a signal at 6165 MeV, with size of 17.8 events or larger, when the data contained a CDF-like signal instead. All this can be studied as a function of K, the "screw factor" affecting the 13-MeV systematic uncertainty assigned by DZERO to their mass measurement.


If you are confused about the procedure outlined above, do not worry -just believe me. I can explain the results and we can then try to interpret them. The result of the exercise is shown below. As you can see, for K=1 the probability that DZERO fitted 17.8 events at 6165 MeV, given a Omega_b producing 5.99 events in their sample at 6054.4 MeV, is very small, about one in 25,000. Very small, sure, but NOT a one-in-hundred-million as we thought by naively comparing the two mass measurements! This is a first thing to take home: if we assume that the CDF is right, AND that DZERO correctly assessed their systematics, this is a one-in-25,000 chance.



Now, look what happens if you blow up the DZERO systematics by a factor three: the probability rises to about one in 200! This is not so rare anymore...

Ok, so the two measurements are not altogether that incompatible, IF we assume that the CDF result is correct AND IF we are willing to admit that the DZERO systematics were assessed bit too happily.

Now, let us do the same exercise from the point of view of DZERO: that is, we assume now for a second that DZERO got mass and production rate right, and that CDF got a wrong result. This time, however, we have a problem. Since, in fact, the measured rate by DZERO is about twice as large as the one measured by CDF, we would have to insert in the CDF histogram not just six Omega_b events in 79, but 31 in 35! The CDF histogram contains only 35 events overall, most of which are for sure background ones.

Since the possibility that the CDF dataset contains 31 Omega_b events is so utterly impossible (by looking at the histogram) that we cannot even bring ourselves to running pseudoexperiments on such a hypothesis, we therefore have to try something different. We can assume that DZERO got the mass right, but the rate wrong. So we construct pseudoexperiments "a' la CDF" by taking 24.4 background events, distributed with a flat shape, and 10.6 signal events, distributed as a Gaussian with mean 6165 MeV (the DZERO measured mass), and with a width equal to sqrt(6.8^2+K^2*0.9^2) MeV: again, we insert a K factor to allow for a variation of the systematic uncertainties as measured by CDF.

The result of this exercise is shown below. You can see that the probability remains absolutely ridiculous even for a K factor of 10, which is really too much to buy, even for a much less careful experiment than CDF.



What to get from the above graph ? We find that the possibility that DZERO is right, and CDF messed up their mass measurement, is basically zero. So, of the two hypotheses, only one remains. And, as Sherlock Holmes once taught us, once the impossible has been ruled out, the remaining hypothesis, however improbable, is the true one.

Pseudo-experiments do not lie -at most, they can be done mistakenly, but they will usually give the right answer to a well-posed question. And I think I am now convinced, dear reader, beyond any reasonable or unreasonable doubt, that who discovered the Omega_b particle is CDF. However mildly unlikely it may look, DZERO probably picked up a fluctuation mixed up with the true signal, and heavily underestimated their mass systematics.

Comments

Wow. But doesn't this set other results in a new light? Like maybe multi-muons, or ...

dorigo's picture
Kea, DZERO is a fantastic experiment, and they deserve credit for their scientific finds, unless proven otherwise. The latter was the case with the Omega_b, but one underestimated systematic uncertainty should not cast doubt on the 500 physics results published by the experiment in its glorious career!
No, I think we really cannot extrapolate. We can say that their Omega_b signal is badly measured, however.

Cheers,
T.

"And I think I am now convinced, dear reader, beyond any reasonable or unreasonable doubt, that who discovered the Omega_b particle is CDF. However mildly unlikely it may look, DZERO probably picked up a fluctuation mixed up with the true signal, and heavily underestimated their mass systematics." - Tomasso

Hi Tommaso, your conclusion is also justified by a quantum gravity model prediction for mass that baryons should have masses close to an integer when expressed in units of 3/2 multiplied by the electron mass divided by alpha: 1.5*0.511*137 = 105 MeV.

CDF: 6054.4/105 = 57.88

D0 = 6165.0/105 = 58.71

The CDF mass is closer to an integer than D0, so it is more likely correct. This quantum gravity model attributes mass to an integer number of massive particles which interact with hadrons and leptons, giving them their masses. Like Dalton's early idea of integer masses for atoms, it's not exact because of the possibility of isotopes (e.g. the mass of chlorine was held up against Dalton's idea until mass spectrometry showed that chlorine is a mixture of isotopes with differing numbers of massive neutrons) not to mention the mass defect due to variations in binding energy. But ilike Dalton's idea, it is approximately correct for all known hadron and leptons:

If a particle is a baryon, it’s mass should in general be close to an integer when expressed in units of 3/2 multiplied by the electron mass divided by alpha: 1.5*0.511*137 = 105 MeV.

If it is a meson, it’s mass should in general be close to an integer when expressed in units of 2/2 multiplied by the electron mass divided by alpha: 1*0.511*137 = 70 MeV. E.g. pion mass masses are about 140 MeV.

If it is a lepton apart from the electron (the electron is the most complex particle), it’s mass should in general be close to an integer when expressed in units of 1/2 multiplied by the electron mass divided by alpha: 0.5*0.511*137 = 35 MeV. E.g., muon mass is about 105 MeV.

Every mass apart form the electron is predictable by the simple expression: mass = 35n(N+1) MeV, where n is the number of real particles in the particle core (hence n = 1 for leptons, n = 2 for mesons, n = 3 for baryons), and N is is the integer number of ‘Higgs field’ type massive particles that interact with gravitons directly and then couple their inertial and gravitational mass to that fermion (lepton or baryon) or meson (boson) standard model core.

From analogy to the shell structure of nuclear physics where there are highly stable or ‘magic number’ configurations like 2, 8 and 50, and we can use n = 1, 2, and 3, and N = 1, 2, 8 and 50 to predict the most stable masses of fermions besides the electron, and also the masses of bosons (mesons):

For leptons, n = 1 and N = 2 gives the muon: 35n(N+1) = 105 MeV.
For mesons, n = 2 and N = 1 gives the pion: 35n(N+1) = 140 MeV.
For baryons, n = 3 and N = 8 gives nucleons: 35n(N+1) = 945 MeV.
For leptons, n = 1 and N = 50 gives tauons: 35n(N+1) = 1785 MeV.

It's just a rough model, but it is substantiated by a quantum gravity path integral model for low energy physics, which shows from the force of gravity that all gravitational charges (masses) are derived from a single building block of mass, which is equal the mass of the Z_0 neutral weak boson, 91 GeV. This mass is coupled weakly to most particles due to the shielding due to vacuum polarization around standard model particle cores.

And how would you account for massive neutrinos?

Sorry Tommaso, I possibly ended up feeding him before seeing the other posts. Please feel free to erase both my posts if it will help keeping the signal/noise ratio high.

dorigo's picture
Dear Nigel,

Thank you for your support, but I fail to understand how the fine structure constant can be all it takes to predict particle masses, especially for hadrons which are quarks bound by the strong force. Further, I find it hard to believe that one should be using alpha as a magic number, since it is not a constant but a variable depending on the process.

Now I do not understand much of quantum gravity, but the little I know lends me to doubt of the predictive power of your formula... Anyway, keep working at it.

Cheers,
T.

Hi Tommaso,

The reason why alpha is a variable is vacuum polarization, e.g. at 91 GeV it falls from 1/137.036... to just 1/128.5 as reported in lepton collisions by Levine et al, in PRL, in 1997.

Alpha is the ratio of the low energy electric charge of an electron (i.e. the textbook charge for collisions and low energy physics generally below about 1 MeV energy, which corresponds to the required low-energy or IR cutoff on the logarithmic running coupling for QED interactions) to the bare core (high energy) charge of an electron.

To see why this is so, consider the QED electric charge suggested by the repulsive force generated by a simple exchange of virtual photons (field quanta) between two electrons.

Virtual photons are generated by virtual fermion annihilation loops in the vacuum (whereby virtual photons are being generated constantly by the annihilation of virtual fermion pairs, in an endless cycle). Now, Heisenberg’s uncertainty principle says that the product of the uncertainties in momentum and distance is at least h-bar. Let uncertainty in momentum p = mc, and the uncertainty in distance be x = ct. Hence the product of momentum and distance, px = (mc).(ct) = (mc^2)t = Et which of course is still equal to h-bar, where E is energy (from Einstein’s mass-energy equivalence). This Heisenberg relationship (the product of energy and time equalling h-bar) is used in quantum field theory to determine the relationship between particle energy and lifetime: E = h-bar/t. The maximum possible range of a virtual particle is equal to its lifetime t multiplied by c. Now for the slightly clever bit:

px = h-bar implies (when remembering p = mc, and E = mc^2):

x = h-bar /p = h-bar /(mc) = h-bar*c/E

so E = h-bar*c/x

when using the classical definition of energy as force times distance (E = Fx, i.e. the energy required to exert force F over distance x in direction of the force is E):

F = E/x = (h-bar*c/x)/x

= h-bar*c/x^2

Notice that we have calculated the repulsive force between two electrons via quantum mechanics, and obtained a quantitative prediction complete with inverse-square law. When you compare this result to the usual coulomb force prediction for the force between two electrons for low energy physics, you find that the force above from quantum mechanics (neglecting the vacuum polarization shielding of the core of an electron) is about 137.036 bigger than that from coulomb's law. Hence vacuum polariation reduces the bare core charge of an electron by a factor equal to the fine structure constant.

This 137.036... shielding factor applies to the vacuum polarzation region which extends from the bare core of an electron (believed by many people to be Planck size) out to the limiting distance for the pair production by a steady electric field, which is the IR cutoff and is predicted by Schwinger's formula: 1.3*10^18 volts/metre (equation 359 in Dyson’s http://arxiv.org/abs/quant-ph/0608140 or equation 8.20 in Luis Alvarez-Gaume, and Miguel A. Vazquez-Mozo’s http://arxiv.org/abs/hep-th/0510040 ). This electric field occurs out to 33 femtometres from the electron core, so all vacuum polarization (spacetime loops) and thus all vacuum shielding of electric charge occurs within 33 fm from the core of an electron.

Do you see the point now, that the 137.036 factor is the complete vacuum shielding? It's a bit like going up a mountain. At sea level, you're shielded from cosmic radiation by 10 tons/square metre of atmosphere (like being behind a 10 metres thick water radiation shield), which cuts the cosmic radiation by a factor of 100. As you get more energy to climb a mountain or go up in an aircraft to get nearer space, there is less shield between you and space so the cosmic radiation level increases. Flying at 36,000 feet, there is a 20 fold increase in cosmic radiation from 0.01 mR/hour to 0.20 mR/hr, and on the Moon (no atomsphere) you get totally unshielded radiation at 1 mR/hr.

Similarly, the reason why the 137.036 number falls at higher energy is because it is a shielding factor, and as you collide particles harder, get approach ever more closely, so there is less polarized vacuum between them to shield their electric charges. Hope this helps.

Hi Tommaso,

The reason why alpha is a variable is vacuum polarization, e.g. at 91 GeV it falls from 1/137.036... to just 1/128.5 as reported in lepton collisions by Levine et al, in PRL, in 1997.

Alpha is the ratio of the low energy electric charge of an electron (i.e. the textbook charge for collisions and low energy physics generally below about 1 MeV energy, which corresponds to the required low-energy or IR cutoff on the logarithmic running coupling for QED interactions) to the bare core (high energy) charge of an electron.

To see why this is so, consider the QED electric charge suggested by the repulsive force generated by a simple exchange of virtual photons (field quanta) between two electrons.

Virtual photons are generated by virtual fermion annihilation loops in the vacuum (whereby virtual photons are being generated constantly by the annihilation of virtual fermion pairs, in an endless cycle). Now, Heisenberg’s uncertainty principle says that the product of the uncertainties in momentum and distance is at least h-bar. Let uncertainty in momentum for virtual photons be p = mc, and the uncertainty in distance be x = ct. Hence the product of momentum and distance, px = (mc).(ct) = (mc^2)*t = Et which of course is still equal to h-bar, where E is energy (from Einstein’s mass-energy equivalence). This Heisenberg relationship (the product of energy and time equalling h-bar) is used in quantum field theory to determine the relationship between particle energy and lifetime: E = h-bar/ t. The maximum possible range of a virtual particle is equal to its mean lifetime t multiplied by c. Now for the slightly clever bit:

px = h-bar implies (when remembering p = mc, and E = mc^2):

x = h-bar / p = h-bar /(mc) = h-bar*c/E

so: E = h-bar*c/x

when using the classical definition of energy as force times distance (E = Fx, i.e. the energy required to exert force F over distance x in direction of the force is E):

F = E/x = (h-bar*c/x)/x

= h-bar*c/x^2

Notice that we have calculated the repulsive force between two electrons via quantum mechanics, and obtained a quantitative prediction complete with inverse-square law. When you compare this result to the usual coulomb force prediction for the force between two electrons for low energy physics, you find that the force above from quantum mechanics (neglecting the vacuum polarization shielding of the core of an electron) is about 137.036 bigger than that from coulomb's law. Hence vacuum polariation reduces the bare core charge of an electron by a factor equal to the fine structure constant.

This 137.036... shielding factor applies to the vacuum polarzation region which extends from the bare core of an electron (believed by many people to be Planck size) out to the limiting distance for the pair production by a steady electric field, which is the IR cutoff and is predicted by Schwinger's formula: 1.3*10^18 volts/metre (equation 359 in Dyson’s http://arxiv.org/abs/quant-ph/0608140 or equation 8.20 in Luis Alvarez-Gaume, and Miguel A. Vazquez-Mozo’s http://arxiv.org/abs/hep-th/0510040 ). This electric field occurs out to 33 femtometres from the electron core, so all vacuum polarization (spacetime loops) and thus all vacuum shielding of electric charge occurs within 33 fm from the core of an electron.

Do you see the point now, that the 137.036 factor is the complete vacuum shielding? It's a bit like going up a mountain. At sea level, you're shielded from cosmic radiation by 10 tons/square metre of atmosphere (like being behind a 10 metres thick water radiation shield), which cuts the cosmic radiation by a factor of 100. As you get more energy to climb a mountain or go up in an aircraft to get nearer space, there is less shield between you and space so the cosmic radiation level increases. Flying at 36,000 feet, there is a 20 fold increase in cosmic radiation from 0.01 mR/hour to 0.20 mR/hr, and on the Moon (no atomsphere) you get totally unshielded radiation at 1 mR/hr.

Similarly, the reason why the 137.036 number falls at higher energy is because it is a shielding factor, and as you collide particles harder, get approach ever more closely, so there is less polarized vacuum between them to shield their electric charges. Hope this helps, and that you don't mind me explaining the distinction between the running coupling and the fine structure constant. I can't understand why the mainstream refuses to think physically about vacuum polarization shielding electric charge (which is a simple physical fact in capacitor dielectrics which used to be an area of electronics I worked in).

Sorry the first time I pressed submit the internet connection failed, and when it reconnected there comment wasn't there so tried afain after slight editing, anow both versions have appeared!

'I fail to understand how the fine structure constant can be all it takes to predict particle masses, especially for hadrons which are quarks bound by the strong force.'

There's a physical model of quantum gravity behind it, and the binding of quarks inside hadrons by the strong force doesn't imply that the strong force couples the hadron to a Higgs-type massive field in the vacuum! All quarks have electric charges which are more important strong forces (colour charges) for coupling to external Higgs type mass fields, because they are longer ranged. The strong interaction is very short ranged, electric fields have longer range and can interact with the surrounding vacuum.

dorigo's picture
Nigel,

I am still waiting for an answer on why the electromagnetic interactions are all it matters for the mass of hadrons, for which the bound is governed by strong ones.

You could have instead saved me the above text, which is good for high-school students anyway, but I understand your need to broadcast your learned lesson. However, it was your choice and I do not discuss it.

You could also have saved me the final "Hope this helps", too. In this latter case, letting your ego roam loose has a nocuous impact on my will to discuss with you. Do you think you can teach me quantum electrodynamics ? Answer frankly, instead than taking an attitude.

Cheers,
T.

Tommasso, don't let these guys get up your nose. Nigel cook has been propagating BS online for many years now - do what I do and consider it as a joke :)

Hi Tommaso,

'I am still waiting for an answer on why the electromagnetic interactions are all it matters for the mass of hadrons, for which the bound is governed by strong ones.'

Thank you for pointing out that my reply was not adequate for you regarding the relationship of strong interactions to mass:

(1) Mass/energy is the charge of quantum gravity.

(2) Quantum gravity is related to electromagnetism, they're both long range inverse square law forces and I've got an SU(2) mechanism which makes quantitative predictions for the forces of each which are correct. This is why mass depends on electromagnetic interactions between particle cores and the vacuum. This has been suppressed by string theory peer-reviewers at IoP journals.

For this reason I didn't want to get your blog bogged down in this, and just commented on the quantization of masses, by analogy to Dalton, who didn't even have a model of nuclear structure when analyzing masses of atoms.

Science doesn't proceed direct from first theory to final theory in one step.

"In this latter case, letting your ego roam loose has a nocuous impact on my will to discuss with you. Do you think you can teach me quantum electrodynamics ? Answer frankly, instead than taking an attitude."

If you think I have an ego compared to string theorists and others who can't make predictions, you are welcome to your opinion. I suggest you delete all my comments from the thread instead of being abusive and insulting when I tried to help by replying to you insult. Best wishes, Nige

dorigo's picture
Where did I insult you, Nige ? I asked you whether you think you can teach me QED, which I learned long ago. You took an attitude, not I. Sorry if you felt insulted, anyway.

Cheers,
T.

dorigo's picture
And to be clear, Nige: I have nothing against your theory, nor against your discussing it here. Only, please avoid acting as if you are teaching me things I know. That is all I ask - I have my own ego, and it is largish and sensitive.

Cheers,
T.

Could CDF and D0 have discovered different particles? If they have, what could the properties of the non-Omega-B particle be, besides having a different mass? Any ideas? On TGD Diary http://matpitka.blogspot.com/2009/05/which-omega-b-is-real-one-or-are-bo... Matti Pitkanen speculates about "p-Adic Particle Massivation". I'm not sure what that is. Tommaso do you know whether his theory is more on the speculative or the orthodox side?

Any replies from D0 about CDF's rival claim?

Cheers,
Martin

dorigo's picture
Hi Martin,
no, I do not think they can have discovered different particles, because if DZERO's Omega_b was as they measure it, CDF would have seen another 30-event spike at 6.16 GeV -while they saw one or two events there.

I only know of informal chat by DZERO members, and I prefer to avoid discussing those here.
Cheers,
T.

D0 may have used 1 MeV = 1,024 keV ;-), then it works pretty correctly. By the way, with all those pseudoexperimenters, won't you become a pseudoexperimenter much like this thread has become a pseudocomment threat with so many Nigel Cooks in it? He's apparently fiollowing the program of Arthur Eddington, explaining everything out of 1/136 err 1/137.

dorigo's picture
You know, Lubos, it's true - I have been fiddling with this toy program a little bit too much lately. I will be back with real physics very soon, though.

Cheers,
T.

Great to hear, you still have at least 15 orders of magnitude - and exp(15) bound states similar to Omega_b - towards the Planck scale. ;-)

Hi Tommaso,

a very nice exercise. In fact, it would be nice to hear a seminar on this topic, with a presentation of the D0 and the CDF analyses, followed by your statistical analysis. Is there any way to get this into the physics mainstream? Will the PDG pick up on this? Maybe it is not so important. Or, would it be, if these were Z' signals at the LHC...

regards,
Michael

dorigo's picture
Hi Michael,

well, I agree -if these were two signals for a new particle, the matter would be so red-hot that no investment of time and thought would on it be superfluous. It would be a maelstrom!

For the Omega_b, I think it was important to show that the mass is in the right ballpark where theoretical predictions put it. The rest is arguably just competition between us and them.

In general, I think the exercise above does constitute a simple means of quickly assessing how likely is one scenario with respect to another. But the PDG people usually do their own stuff in cases such as this one -I'd have to lobby Weiming to get this used there :)

Cheers,
T.

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