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By Johannes Koelman | August 15th 2009 07:36 AM | 66 comments | Print | E-mail | Track Comments
About Johannes

I am a Dutchman, currently living in the US. Following a PhD in theoretical physics (spin-polarized quantum systems*) I entered a Global Fortune...

View Johannes's Profile
Google “E=mc2 is wrong” and you get 1,060 hits. Google “E=mc2 is correct” and you get a mere 138 hits. There you have it. It took us a more than a century, but finally this crazy inconsistent theory of relativity got outvoted. Common sense cries victory!

Fortunately, science does not work that way. Science is no democracy, and we do not render a theory invalid by popular vote. Einstein's theory of relativity has stood the test of time and its correctness is beyond any doubt. But... there is an issue with what is arguably the most famous equation in the history of natural sciences.

So what is the problem with Einstein's mass-energy relation?



Well, to put it bluntly, there is no such thing as a mass-energy relation. What does exist is a mass-energy-momentum relation. The equation Einstein came up with more than a century ago can be considered a degenerate form of the mass-energy-momentum relation for vanishing momentum. Einstein was very well aware of this, and in later papers repetitively stressed that his mass-energy equation is strictly limited to observers co-moving with the object under study. However, very, very few people seem to have paid attention to Einstein's warnings, nor to any of the more recent warnings. Even worse, the vast majority of authors of popular science books take great liberty in applying E=mc2 to objects moving at speeds close to the speed of light, and then declare mass to increase with velocity in an attempt to recover consistency in what has become an incoherent mix of relativistic and Newtonian dynamics. Theoretical physicist Lev Okun refers to this practice as a “pedagogical virus”.

What I consider truly amazing, is how few people are aware of the mass-energy-momentum relation. In contrast to the widely popularized equation E=mc2, the mass-energy-momentum relation is a direct result of the fundamental principles of relativity theory, and provides true insight into the basics of relativity. Moreover, and contrary to what one might expect, the mass-energy-momentum relation is far from complicated. In fact, the mass-energy-momentum relation does not even need a mathematical equation, a simple drawing with annotations suffices.


Einstein meets Pythagoras: the mass-energy-momentum relation. In the rectangular triangle, the hypotenuse represents energy times c (c denoting the speed of light), the vertical edge momentum times c2, and the base mass times c3.

The above figure graphically captures the mass-energy-momentum relation for a particle of mass m and total energy E, moving at velocity v. The parameter c denotes the speed of light. Shown is a right triangle with labeled edges. The hypotenuse labeled Ec is proportional to the energy of the particle, and has length energy E times speed of light c. The vertical edge labeled Ev is proportional to the momentum of the particle and has length E times v. Finally, the base labeled mc3 is proportional to the mass of the particle and has length m times c3.

The full relativistic kinematics is captured in this annotated triangle. Knowing two out of the three quantities mass, energy and momentum, using this simple diagram one can easily derive the third. For instance, suppose one wants to know the total energy of a particle, when given that it moves at a velocity of 3/5 the speed of light. With v:c equal to 3:5, it is clear that the vertical edge Ev and the hypotenuse Ec are in the same ratio. Applying the Pythagorean theorem immediately leads to the conclusion that we are dealing with a 3:4:5 triangle. Hence, the hypotenuse is 5/4 times the base: E = 5/4 mc2. Who told you relativity theory is heavy stuff?

We can also use the above triangle to derive some generic relativistic results. For instance, as the vertical edge can not be longer than the hypotenuse, one of the core axioms of relativity follows: no particle can move with a speed v larger than the speed of light c. Notice that to achieve this result, we don't need any misleading constructions like 'mass increases with velocity'.

Also the extreme case of m = 0, applicable to massless particles like photons, is well captured in the triangle. For m = 0 the triangle collapses to a vertical line element and it follows immediately that Ev = Ec or v = c. Massless particles move at the speed of light.

Needless to say that Einsteins mass-energy relationship is captured as well in the special case Ev = 0 (i.e. for the triangle collapsing into a horizontal line element). For those brave enough to battle some math equations: it can also be shown that when Ev is non-zero but much smaller than Ec, the non-relativistic (Newtonian) limit is firmly captured in the mass-energy-momentum triangle. For Ev << Ec the triangle takes a flat shape with Ec ≈ mc3 so that the Pythagorean equation can be written (Ev)2 = (Ec)2 – (mc3)2 = (Ec + mc3)(Ec - mc3) ≈ 2mc3(Ec
– mc3). Hence, Ec – mc3 = (Ev)2/2mc3 or E = mc2 + (Ev)2/2mc4 ≈ mc2 + (mc2)2v2/(2mc4) = mc2 + mv2/2. If you managed to follow this math reasoning, surely you will recognize the well-known Newtonian kinetic energy expression in this result.

A few more relativistic insights are captured in the mass-energy-momentum triangle. For instance, the mere fact that the momentum edge is labeled not mv (nor mc2v) but rather Ev is significant. It stresses the fact that the total energy (and not mass) is a measure of inertia. Once one realizes this, it should be clear that statements like “mass increases with velocity” are plainly wrong.

You might wonder, why is it that this mass-energy-momentum relation can be represented in a simple rectangular triangle? This question brings us to the heart of Einstein's relativity theory. In four-dimensional spacetime, energy and momentum lose their meaning as separate quantities. Instead, a four-component spacetime vector emerges that describes energy and momentum in a unified fashion. In loose loose terms one can envision this spacetime vector as a flow of energy at speed v in space and speed c in time. The space (Ev) and time (Ec) components of this energy-momentum vector do depend on the frame of reference of the observer, but the length of this vector is an absolute quantity, that is independent of the choice of observe. This quantity is called mass.

In a normal Euclidean space, the length of a vector is determined by a Pythagorean sum of the components. Spacetime vectors behave subtly different as the space and time components contribute to the vector length with opposing signs. As a consequence, when grouped into a space and a time component, the length of a spacetime vector is given by the Pythagorean difference of the two components. What results is a rectangular triangle with the length of the spacetime vector being represented by one of the short edges.

Will we ever see mass-energy-momentum triangles replacing E=mc2 as slogan on t-shirts? I don't hold my breath. A technically superior product in itself is unlikely to replace a strong brand. And “E=mc2” certainly is a strong brand for 20th century physics. In fact, it is more than that. A true symbol and icon of mankind's intellectual achievements. The fact that it is more than often represented in an inconsistent way is a shame, but can not take away that luster.

--- Follow-up posting: click here ---

Comments

Did that hammock come with simon cowell, or did you add that separate?

Johannes Koelman's picture
Simon Cowell is there to scare away from this blog any Idol who might come up with the bright idea to abuse relativity theory. Just in case...

my name is venkatesh ,
i am studing in india in narayana iit academy ,
in a.p hyderabad,
few days back i developed a rheory based on special theory of relativity ,
i am studing +2 ,
this is according to my imagination it can explain total what that cannot be explained by einstein of black holes etc.
advantages of what i imagined
..................E=MC2=KNC2

DOU KNOW WHAT IS MEANT BY KNC2 ?
IF U WANT TO KNOW THEN JOIN ?
THIS IS ACCORING TO MY IMAGINATOIN I PREPARED A NOTES .
WHICH SUPPORTS THIS FORMULAE

ADVANTAGES OF WHAT I PREPARED

1.WE CAN GET THE ABSOLUTE REASON FOR BIG BANG THEORY
2.ACCORDING TO ME I CAN TELL THE SHAPE OF UNIVERSE
3.I CAN GIVE THE REASON FOR BLACK HOLES
4.WHAT IS HAPPENING TO A METERIAL
WHEN IT IS ENTERING INTO BLACK HOLE ?
5.WAS THIS UNIVERSE WAS FORMED FOR HUMAN?
6.WHAT IS HAPPENING TO THE HUMAN AFTER DEATH?
IT CAN EXPLAIN PHILOSOPHY OF LIFE?
7.HOW DOES THE CREATION WAS STARTED AND HOW THE DISTRECTION OF UNIVERSE WILL START.
8.IS THERE ANY SUPREMU POWER FOR THIS UNIVERSE
9.THERE IS ONLY SINGLE FORCE RESPONSIBLE FOR THE FORMATION OF UNIVERSE AND WHAT IS THE REASON FOR DIFFERENT FORCES IN NATURE?
10.WHAT IS THE SUPREME FORCE OF IT ?
11.IT CAN EXPLAIN THE LAW OF CONSERVATION GF ENERGY?
this are the advantages of it my mail id
"venkateshT4094030@gmail.com

The formula is written in Latin. The "E' is "energia," Latin for energy. The "m" is "massa," Latin for mass. The "c" is "celeritas," Latin for speed (of light).

I would imagine it would make a nice Tshirt. Would go well with my Doppler shifted Einstein and my Maxwell's Equations/Swarzchild Radius T-shirts.

Correction: Schwarschild

Hank's picture
We have the Maxwell shirt, at least.   


Johannes Koelman's picture
"We have the Maxwell shirt, at least."

Can I order the relativistically covariant version?

Just another example of elitist nerds trying to show that they are better and smarter than the public.

Hank's picture
Elitism is back.   I think it's time society again be allowed to agree that science PhDs are smarter than gas station attendants without politically correct platitudes.   It isn't a value judgment, every one gets one vote ... but saying the smartest people are not smarter than dumber people is like saying 'the public' can all be better quarterbacks than Peyton Manning or outrun Usain Bolt.

Fred Phillips's picture
We're more educated than gas-station attendants, but smarter? I'm not sure. Did you see the cute movie where Einstein, while at Princeton, encourages romance between his niece (Meg Ryan) and a garage mechanic? (Walter Matthau is in it too.)
Come to think of it, with all the layoffs of knowledge workers in the current economy, I'd be surprised if there has not been an increase in PhD gas-station attendants.



You write "Einstein's theory of relativity has stood the test of time and its correctness is beyond any doubt" and so reveal a basic lack of understanding of the concept of a 'theory'. A theory is never beyond doubt. It is never taken as correct, only not disproven. Not the same things at all. I am a research physicist and I, for one, would seriously question the statement that this theory has 'stood the test of time'. Given the strictness of the underlying premise of an 'inertial frame of reference', I question that any of the so-called 'tests' done to date are legitimate tests. Personally, I hold serious, objective misgivings about the validity of the special theory and I am certainly not alone in the broader community of physicists worldwide. Unfortunately, the media has canonized both the author of this theory and the theory itself to the point that it is considered heretical or irrational to even question the theory. This state stands as a basic failure of the science communitiy to remain skeptical and questioning. Once we begin taking theory as 'dogma', spoken ex cathedra and thus unchallengeble, we are in trouble. After all, that was once the case for Newtonian mechanics!

Johannes Koelman's picture
Ken, Einstein's relativity theory is beyond any doubt just like Newton's classical mechanics was, and still is, beyond any doubt. Obviously since Einstein we know that Newton's theory has limited application range. That, however, does not render Newton's theory in any way wrong.
In the same way, a future Quantum Gravity theory will clarify where Einstein's Relativity Theories will lose it's meaning. (We already know a few circumstances where it has to break down.)

You have doubts about Einstein's Special Relativity theory. Fair enough. Anyone is most welcome to indicate areas where this theory will fail. In fact, I know of several research programs dealing with variants of Special Relativity. But the point is, you better do this building on Einstein's work. Ignoring the fact that physics is a cumulative intellectual enterprise won't get anyone far.

universe is expanding how
to know this reason i can give the answer for it
according to what i imagined

Any way you could present this in English?

"In four-dimensional spacetime, energy and momentum lose their meaning as separate quantities. " How is that different in the world we experience other than thinking of one as the engine and the other as the expression?

Hfarmer's picture
I have been reading the published literature about the inflationary theories and frankly they make about as much sense as that haiku.  They fit the data...but they are effective theories at best not final answers.  

What's the mapping between your triangle and this one en.wikipedia.org/wiki/File:Relativistic_Dynamics.svg ?

But...I thought e=mc2 is the foundation of nuclear physics. How else does fission turn matter into energy if not through the power of e=mc2? How does the sun work, if it's not turning parts of its hydrogen into energy?

Johannes Koelman's picture
Alex, the equation E0=mc2 is correct. The total energy of an object at rest (E0) is equal to its mass m (times the square of the speed of light). What is incorrect, is to apply this equation to moving objects (ie. to ignore the subscript "0"). Einstein meant the energy in his equation to represent rest-energy, unfortunately many people ignore that proviso (or are even unaware).

Ahhh. I get it now, thanks!

Radhakrishna's picture
Very nicely written. The concept of variation in the mass with velocity has been in our Text Book for several  years, only indicate that once the concept concritised - right or wrong - to change it , extreemely difficult. Slowly the idea that whan a particle mooves with a velocity,  mass remain same, what changes is the momentum - appearing in few Text books. I wish to know more about this explanation. Will you provide some links? Your triangle method is worth to study further.  

Some one said that Newton is wrong, Einstein is wrong - since all theory has the same fate - one or other day they become invalid.

But the fact is that both fellows gave the theories and they are  not wrong - they may be having limitations. For example Newton has limitation if he mooves very fast ! 

Limitaion is diffferent than the false theory. Theory requires modification and refinement. That is the way Science grows. If it is not, then it is not Science - it is Nonsense. 
 

Johannes Koelman's picture
Thank you Radha. Indeed, some physics textbooks start appearing that correctly treat mass as invariant. However, it takes time for the trend to reverse, and the majority of textbooks still ignore the fact that it is energy (not mass) that provides inertia and that couples to gravity.
Notable exception is the superb book "Spacetime Physics" by Taylor and Wheeler. I think that is the best link I can provide you. Taylor's site also contains a link to the first chapter of the first edition of the book.
In some future blogs I plan to delve deeper into relativity theory, and to showcase simple ways to build the right intuition in this area of physics. But be patient!

Radhakrishna's picture
Thank U Kolelman. I got that book, yet to read. Wheeler a great Physicist and writer. After going through I will write. 
 Iam eagerly waiting for your article on Relativity.
Krishna

You know something's really wrong with the system of teaching basic science around the world when most physicists have to begin articles with something like "... a popular misconception, bolstered unfairly by text-books is..."

Can you elucidate how Quantum Gravity has the potential to refine Special Relativity? And where does Special Relativity break down? Most science books stop at mentioning the breakdown of General Relativity in a singularity.

In a side note:
One has trolls on scientificblogging too? Why do they have to be Indians? And people from Hyderabad, to boot?





Actually, 'E=mc2 is correct' gets 2,440,000 hits, and 'E=mc2 is wrong' only gets 72,100 hits on google. I don't think that the amount of hits for either of these two things could change so drastically in a month...maybe you ought to get your facts right the next time you write an article.

Johannes Koelman's picture
Anon, please note that the Google search was done with exact matching of the search strings (hence the double quotes).

talk about manufactured controversy. i don't know anybody who would describe themselves as having even a rudimentary knowledge of physics, who doesn't know about gamma. certainly i was taught about it in high school physics. when you say "most people don't know..." you're aware you're talking about the people who take medical advice from oprah, right?

Are you not taking into account that Einstein actually said:
E = (gamma) * m * c^2

gamma is a coefficient that takes into account the speed of the particle so that the energy relation works up to the speed of light.

It is the gamma that makes relativity work, otherwise scientists refer to the equation without the gamma as the "rest energy" equation, because, when velocity is zero, gamma = 1.

The equation for gamma is this:
gamma = 1 / sqrt( 1 - ( v^2 / c^2 ) )

This is straight out of my modern physics class from my undergrad.

Johannes Koelman's picture
"Are you not taking into account that Einstein actually said:
E = (gamma) * m * c^2   [..]    gamma = 1 / sqrt( 1 - ( v^2 / c^2 ) )"


That is a correct, yet complicated, way to represent the above mass-energy-momentum triangle. Unfortunately Einstein never wrote that. Einstein focused on the gamma = 1 limiting case.

Way too many words for absolutely no substance.
the energy-word-interest relation of this blog is close to nothing.

Didn't get a thing.....but that t-shirt was fabulous..............From where can I buy it? Please provide more information over it. Provide links to related topics if possible.keep posting. Will be visiting back soon.

Ok, so you have answered a question for me - "Where does a particles momentum go when the particle is converted to energy?" Your answer suggests that it is simply added to the mass conversion energy.

But now you have posed me an even nastier problem.

Given that within a system energy is constant (irrespective of what form that energy takes, mass, velocity, heat, light etc), then could I pose a thought experiment for you.

A closed system has three bodies - you, me, and a small mass. I am approaching you at 20%c and the small mass is approaching me at 60%c (and approaching you at 80%c).

You and I each have a device able to capture the mass and convert it to energy.

First off, as the mass gets to me, I capture it and convert it using your previous example of E=5/4mc2 then as I later pass you I hand the massless energy to you.

Second, as the mass gets to me, I let it pass and later you capture and convert it, but now the energy released is E=5/3mc2 a short time later, I pass you without handing any energy over.

How do you explain the 5/12mc2 energy anomaly?

It seems as though the energy I am carrying to you still posses momentum energy due to the fact that it is still travelling at 20%c towards you, yet how can this be as it is massless? As I pass by you, the two systems are identical, yet in the latter you will be much 'hotter' than in the former.

The only way to balance this is for the energy I hand you to increase by the missing 5/12ths due to the speed of 20%c involved in the hand over. If I am approaching you at 20%c and I emit a joule of photonic energy at you, will it be 1.417 joules when you collect it ??

Derek

Johannes Koelman's picture
Derek --you are pre-empting me on what I was planning to do in a future blog: demonstrating how relativistic collision calculations can be made based on Pythagorean triangles.
You have to be careful in your assumptions though:
Ok, so you have answered a question for me - "Where does a particles
momentum go when the particle is converted to energy?" Your answer
suggests that it is simply added to the mass conversion energy.

Indeed, mass is not an additive quantity and can disappear. Be aware, however, that both energy and momentum (the full so-called 4-momentum) is conserved.
A closed system has three bodies - you, me, and a small mass. I am
approaching you at 20%c and the small mass is approaching me at 60%c
(and approaching you at 80%c).

Be aware that you can not use Galilean velocity addition here!

Good luck, you are on the right track! :)

STOP TEASING

The only track I am set on is the one to the Sanatorium !!

What is wrong with my thought experiment ? Irrespective of Galilean velocity addition, If the particle is travelling towards me, and me and it are travelling towards you, the particle will have more velocity energy when you convert it than when I convert it. So how is energy conserved ?? Where is the difference, or does the energy just look different to me because I am travelling towards you? - but if that is the case every body will see other bodies energies all wrong depending on their respective velocities.

What do you mean by "mass is not an additive quantity and can disappear"? Do you mean literally disappear or simply convert into energy ??

Also you say "both energy and momentum (the full so-called 4-momentum) is conserved." Now my math and my physics is not up to understanding the Four-momentum explained on Wikepedia, but are you saying that the energy of the momentum is conserved (as you have shown) or are you saying that some kinetic aspect of the momentum is conserved? in which case, how is this manifest on the ball of energy I am carrying along with me having converted the moving mass into energy ? If we ever managed to convert that energy back into mass again, would the 'invisible' momentum component make the mass go whizzing off under the conserved momentum ???

Derek

Johannes,

Another issue which has been bugging me.

Momentum has a vector component, information which 'tells' the mass which direction the momentum is 'going'. When momentum gets absorbed into the energy conversion, where does the vector information go?

Derek

A photon has a vector component.

When it hits me and combines with me, I absorb its energy, but what has happened to its vector information?

What aspect of inertia did the photon have such that it knew which way to continue to travel?

Vector is a human construction to describe a direction, but how does momentum 'describe' or 'store' this information?

Derek

Hmmm,

OK, I have been looking at the various 'flavours' of energy - Potential, kinetic, light, heat, chemical etc. and I have realised that they ALL involve vectors.

I have read that the energy of a photon is Pc where P is the photons momentum - OK, so it has a vectored velocity, but where is its mass? Is momentum something that all energy possesses irrespective of if it is massive or massless ? If that is the case, how can momentum of mass be turned into energy, because then you have energy from energy... Are there different sorts of momentum? one for mass and one for energy ??

Then, if a chunk of mass with momentum is converted into energy, and that energy also has momentum, does it mean that the vector of the original mass is preserved, i.e. the energy all flows in the direction of the mass? And when that energy gets absorbed by an object, how can massless momentum affect the object it has been absorbed by?

Are those the straps of a straight jacket I feel tightening around me ??

Gerhard Adam's picture
I think your confusion is coming from the issue of mass for a photon.  Bear in mind that the mass you're thinking of refers to the inertia of an object, or its rest mass.  Since a photon cannot be brought to rest, it doesn't have a rest mass, so the equations still hold in describing the behavior of the photon, however it would be erroneous to treat it as if it were a tiny billiard ball.

When the energy is absorbed, it is transferred to the atom in question which may raise the energy state of an electron which will cause the electron to emit a photon when it drops back down to its ground state.  So when you consider a photon's interaction (like in moving through glass), it is important to recognize that the photon interacting at the surface, is not the same photon being emitted on the other side.  The only way that could happen is if there is nothing in between to interact with so the photon can travel unimpeded.

Gerhard, please tell me that you are kidding.

Are you seriously suggesting that a photon entering a piece of glass is NOT the same photon that emerges the other side ! That it is destroyed and replaced by an identical replicate in every detail a billion times over.

My day just gets worse and worse. How was this demonstrated and proven? But then, how would you prove that it WAS the same photon ??

Gerhard Adam's picture
Actually it's not that bad.  When an electron is in a higher energy orbital and drops to a lower energy state it emits a photon.  Now imagine that the energy of a photon hits that atom and promotes one of the electrons to such a higher orbital.  When the electron drops back down to ground state, it emits a photon of the same wavelength as the one that hit it.  As a steady progression of these events occurs, it results in the apparent "slowing down" of the photon which is what makes it appear that the light is bending.

That's why I said that, strictly speaking, the same photon that entered isn't the same as the one that leaves.  If a photon traveled straight through, then there would be no basis for the bending that is observed, and it would imply that no interaction has occurred.
That it is destroyed and replaced by an identical replicate in every detail a billion times over.

I think you're getting hung up on the idea that somehow you can identify a specific photon and you're treating them like solid objects.  Besides frequency and wavelength, what characteristic is unique that would allow you to identify a specific photon?  If a photon of a certain frequency/wavelength enters and a photon of the same frequency/wavelength is emitted, how would you distinguish the two?  Electrons can be specifically "prodded" into producing such photon replicas all the time, which is the principle behind lasers.

An imprecise analogy that may help is to imagine whispering a word into someone's ear and them whispering it into someone else's and passing it on.  At the end the word that emerges is identical to the one you started with, although you couldn't actually claim that it came directly from you.  The intermediary steps all "regenerated" it to produce the result.

Johannes Koelman's picture
But now you have posed me an even nastier problem.

The only track I am set on is the one to the Sanatorium !!

My day just gets worse and worse.

Derek -- don't despair. As I said: you are on the right track. What I meant is that it is essential to struggle with these matters until you discover for yourself that relativity is a fully consistent theory.

I have decided to dedicate my next blog entry here to the problem of how to predict relativistic collision outcomes. Hope this will help you progressing on your track towards understanding Special Relativity.


Gerhard, this has troubled me all night and I now think I have discovered the smell.

I have used excitation spectrophotometry, the technique raises electrons to higher energy levels by sending in a wavelength that is heavily absorbed and then analyses the resultant emission profile.

Three things stem from this.

First, the excitation beam is absorbed, it is not re-emitted and relayed through the sample as you claim it would have.
Second, the wavelengths emitted are characteristic of the band gaps present in the sample.
Third, the momentum of the excitation beam is not replicated, the emission is random in all directions.

The second realisation was that if I make a glass from Lithium Fluoride, both are fully ionised so the lithium takes on the electron configuration of Helium and the fluoride takes on the configuration of Neon. No matter how you excite this salt, there are only a small number of band gaps available to this very simple structure and the emitted light is totally characteristic of lithium and fluoride ions. But here is the killer blow - I can pass full spectrum white light into that crystal and have it emerge without a single wavelength missing - yet the LiF does not have the machinery to produce even a tiny subset of all these wavelengths.

The light MUST have passed through without absorption.

But hey, I am the student here... have I missed something ??

Gerhard, perhaps your concept is correct at a different level.

Perhaps a photon is an electromagnetic wave / pulse propagating through the sea of virtual particles which are space at the Plank level.

When I put a sound pulse into a fluid, it has a velocity dependant upon the density of that fluid, it also has a directional vector, so in some way it has momentum. But the fluid is interactive, as my sound pulse compresses / expands the fluid, it allows neighbouring molecules to have more or less space, so the influence of the sound wave is shared with neighbouring molecules and the sound pulse broadens, spreading in fan or cone.

Note to self - the coherence of a sound pulse should be better in a cold substrate than in a hot one in relation to the speed of the sound wave against the vibrational speed of the substrate particles.

In space, the virtual particles popping momentarily into our three space from some other dimension(s) must have virtually no interaction, because as the electromagnetic photon pulse compresses and expands them, neighbouring particles remain uninfluenced so the wave does not spread out. Alternatively, perhaps the electromagnetic capsule is in some way self containing, wrapping the energy pulse in a magnetic bubble which cannot propagate in anything other than the direction of its momentum vector.

This model is at one and the same time a wave and yet because of its capsule nature, also very particle like - A SELF ENCAPSULATED WAVE. No need for Schroedinger uncertainty because an encapsulated wave IS a wave, but also acts like a particle. Being a wave, two waves can pass right through one another, each waves momentum maintaining the flow of each energy pulse discrete from the other. Yet because of its capsule nature, it remains finite so we think of it as a particle.

Derek -- don't despair. As I said: you are on the right track. What I meant is that it is essential to struggle with these matters until you discover for yourself that relativity is a fully consistent theory.

"Close your eyes Grasshopper and you will find the way"

Man has reached his amazing grasp of the universe by learning and sharing - 'Standing on the shoulders of Giants'.

Granted, this is sometimes foolhardy and has led to misconceptions such as - Earth is the centre of the universe - Earth is flat - and numerous flavours of religion - but despite this, it has got us where we are today.

The advent of the Internet further allows people with knowledge to teach people with interest, where prior to the Internet, they would never have had the opportunity to converse, share and develop.

You tell me I am on the right track, and to struggle for understanding, but you have not given me any hint of direction to any of the numerous questions I have shared with you.

Are there answers or are they the questions still to be tackled?

If there are answers and you do not wish to waste your time in dialogue with me, will you at least give me a hint of what to search for.

Derek

Johannes Koelman's picture
I have decided to dedicate my next blog entry here to the problem of
how to predict relativistic collision outcomes. Hope this will help you
progressing on your track towards understanding Special Relativity.

Derek (and others who are interested) -- I have uploaded a follow-up to this article. This follow-up addresses your questions on relativistic mass changes etc. See if it helps (no doubt it will raise further questions, but that's ok).

I guess the topic Johannes was describing is that Einstein’s equation is not relativistically invariant and that was well known to Einstein, who wasn’t able to fix it.

The triangle is from Paul Dirac’s 1928 version of the Einstein equation that is relativistically invariant when taken as a whole, although the separate parts of it are not.

E^2 = (mc^2)^2 + (pc)^2 for rest mass m and momentum p

Dirac also used this equation to predict antimatter like a positron, because the energy has both positive and negative roots.

Although it looks more complicated, the Dirac equation greatly simplifies calculations for high energy physics.

WHAT DID I SAY? The statement is that when using the Dirac equation, relativistic calculations are easier than classical Newtonian calculations, … for which I apologize.

Originally Dirac wrote the formulas in terms of wave mechanics, with probabilities, and for low energy situations that form of his equations is often the most appropriate. So the classical case is an average of what actually happens for many particles.

When high energy levels are used, the particles tend to be larger than their corresponding wavelengths, and the classical equation is a good approximation for single particles and interactions.

All of this is well known in the scientific community and has been for a long time. Johannes is just having fun with us.

you should have googled E=mc^2 not E=mc2

It's surprizing post as I am learning that E=mc^2 from school time and I also had proven so many examples on it So I thought it's a universal truth that E=mc^2.

Johannes Koelman's picture
FF -- this is exactly the point of above post. I wouldn't call E=mc2 a universal truth. The universal truth is E2 - (E v/c)2 = (mc2)2. It is this relation that captures the essence of relativity.

Compare this to the following:

Would you call the statement: "In a rectangular triangle with one vanishing edge, the hypotenuse  equals the non-zero edge" a universal truth?
When relating the edges of a rectangular triangle, I would prefer to reserve the label "universal truth" for Pythagoras' theorem.

Note that I am not stating that E = mc2 is necessarily wrong. It is just that this relation is often misunderstood and frequently misapplied. It would be better if Einstein's mass-energy relation was consistently written E0 = mc2, where E0 indicates the rest energy.

EricFD's picture
You know, now that I've read your article on the mass-energy-momentum relation it makes perfect sense to me. In fact, it seems quite obvious. I guess what is bothering me is that this had never occurred to me before. I appreciate you posting this article. Thank you.

Johannes Koelman's picture
Thanks Eric, the best feedback one could wish for when writing a physics column.

EricFD's picture
You're quite welcome and the feedback is well deserved, Johannes. You have a way of explaining things that make them crystal clear and easy to understand. In fact, in an online astronomy group to which I belong, today the topic of special relativity and the very same issues that you talk about in this article came up. So rather than give them my own inadequate explanation, I instead gave them a link to this very article. Needless to say, it was very well received and greatly appreciated. So you have more fans than you may realize. ;-)

Very best,
Eric


hello sir,
we had read your blog liked it very much. It was very informative and we are very thankful to you. Also, having read it, we came to know that you are practically a genius and wanted to ask you a question, which we had earlier posted on our blog. We had read about Einstein's speed limit and wanted to know why it holds? Why is it required in nature? Also, we had read about quantum entanglement and had a doubt regarding the topic. We are just a bunch of school boys and our knowledge regarding Q.E. is very limited. So, please forgive our ignorance if we might have missed out some point in the thought experiment.

Now, we begin with 2 quantum particles that are entangled such that their spins are in the opposite direction. Now, before any measurement, both the particles exist in a state of superpositioned spin. So, none of the particles "know" where the other might turn out to be spinning when measured. So, now, lets assume that the particles in 2 diff. corners of the universe. Now, we take, suppose particle A and measure it. Lets assume it turns out to be spinning to the right. Now what if I measure the other particle B, just a few seconds after measuring A? B should turn out to be spinning to the left. But how come the information of the collapse of the wavefunction of the particle A reached B so quickly and its probabilities? Doesn't that violate the speed limit? A second ago, B had no idea as to where A was spinning. But just a second later it knew that A was spinning to the right, even though it was in a diff. corner of the universe. And the probabilities of B turing out to be spinning to the left or rightwere altered in the favour of spinning toward left. This problem puzzles us greatly. And hence, we ask for your help in reaching to the heart of it. Please do forgive our ignorance, if we have overlooked a fact somewhere, for we know little of the matter and simply wish to know more by questioning it. We hope to hear from you the problem in the thought experiment soon.
Thank you
A.B.G.D.

Johannes Koelman's picture
Hi A, B, G, D -- thanks for your kind remarks.

The best and deepest questions are often those asked by people who apologize for asking. Hardly ever is the answer to these questions anywhere near obvious. And such is the case with your questions on the universal speed limit, and quantum non-locality.

First your question: "Why is there a universal speed limit?"

The simple answer is "Nobody knows." With that I mean that there is no reason that we know of why a universe could not exist with other laws of physics that poses no such speed limit.

That answer will not make you happy. So let me try to give you one more insight that at least suggests a deeper, more fundamental, reality behind the relativistic speed limit.
I can best phrase this as: "There is no speed limit, there is only one speed."
Surprising? Well, to appreciate this thought, you have to enter the realm of quantum physics. When one investigates the motion of subatomic particles such as electrons, it becomes clear that everything is in relative motion. No particle is ever at rest, as this would violate the uncertainty principle. When investigating this in more detail, it follows that particles like electrons always move at the speed of light, but move back and forth such that the effective speed can be smaller than the speed of light. Consider, for instance, an electron moving forward four steps, and then moving backward one step, all of this at the speed of light. The net effect? An electron moving forward at 3/5 of the speed of light. If you keep this picture in mind, it should be clear that it is impossible for electrons to move faster than light.
The physics behind this so-called "Zitterbewegung" is captured in the Dirac equation. A beautiful representation of the Dirac dynamics for the simple case of an electron moving in one direction is given by the Feynman checkerboard model.

Secondly, your question: "Does quantum entanglement and the collapse of the wave function not cause a violation of the universal speed limit?"

Again a very deep question. The simple answer is "no, there is no violation of the relativistic laws".

How can that be? A first hint is given by the fact that the "action at a distance" as described by you between A and B, can not be utilized to transfer any information between A and B. So if something seems to happen instantaneously, there is nothing that really moves instantaneously. We now have entered the counter-intuitive domain of quantum physics. Quantum physics tells us that if something can not be measured, it really does not exist (I am oversimplifying a bit, but that is the crux of the matter). So even if we observe correlations that seem to 'build' at infinite speed, there is nothing (no particles, and no piece of information) that really travels at a speed beyond the speed of light. It is just because we tend to interpret quantum physics with our classical intuition that we (erroneously) associate some quantum effects with infinite speeds.
 
BTW, thanks for the compliment. But the label 'genius' I prefer to reserve for 'the Feynman's of this world'... :)

Your "just one speed" explanation sounds *exactly* like the dynamics of Conway's Game of Life. There's just one "speed" (the propagation of information from one cell to the next) and different patterns (gliders, spaceships, etc) appear to travel against this background: some directly, others with more of a back-and-forth. But I've gathered from elsewhere that the notion of the universe as a discrete bit pattern with a simple transition function isn't exactly a new one.

And here I thought the "Turing machine in Conway's game of life" was insane...

hello sir,
thank you for your wonderful explanation of the error in the experiment and for the answer to our doubts. we could see that you had simplified the answer to suit our understanding, and we thank you for that. and also,we now realise that we had forgotten to introduce our selves earlier. allow us to do so now, we are members of the group called thinkers.inida and go by the names, Alpha, Beta, Gamma, and Delta and read in tenth standard. We are interested very much in physics and wished to simply understand it better and know the truth. we thank you for aiding us to attain our goal. thank you very much.

also, sir, is it that in case of entanglement, no piece of information travels between the particles? if so, how do they come to know of things like where the other is spinning? also sir is it so that the mass of a body in motion does not increase. if so, what about the formula for calculating M1 from M0. is it false? also, sir you told us about the electrons moving to and fro and this resulting in a velocity lesser than c. does this stop bodies that are much more massive than electrons from moving at a speed greater than c in any way. for we wished to know if there was a deeper inference to the explanation which we have not understood. also, sir, please tell us why this explanation does not go for tachyons. and why is it so that particles moving at velocities greater than c cannot come down to velocities lesser than c?

we await your reply, sir. and hope our questions are not a nuisance for you. thank you once a again for your answer.

BTW, the compliment was well deserved. and it is only your humility, sir, that stops you from realising it.
thank you
A.B.G.D.

Johannes Koelman's picture
Hello A, B, G, D -- you're welcome.

Indeed, there is no signaling and no information traveling associated with entanglement. You are surprised by that, and you should be! I have written a blog about this puzzling aspect of quantum physics (see here). It takes a profound change of perspective to appreciate why this is. It all boils down to us being limited in our intuitive reasoning (and even in our language) to realities corresponding to classical physics. I might spend a future blog entry on this.

On relativistic mass increase: from didactical perspective it is best not to mix up the roles of mass and energy. Rest energy is mass (E0 = mc2), but that is the only energy that can be equated to mass.

Energy increases when a particle speeds up, mass is invariant and doesn't. But you have to couple this with the insight that inertia is related to the total energy of an object and not just its rest energy (or mass). And gravity pulls on any form of energy (photons have energy but no mass, but do get deflected in gravity fields).

About understanding relativity based on the quantum behavior of electrons: for all practical purposes you and I (and everything around us) are clouds of electrons. What I mean is that the day-to-day physical reality we perceive (incl. all of chemistry, biology, etc.) is dictated by the behavior of electrons.

On tachyons: they do fit into a single velocity description, but you have to assume a kind of 'inverted' space-time. But my simple advise is to forget about tachions, they are purely hypothetical anyway.

hello sir,
hope all is well there. thank you very much for your reply. it was very informative. but we must admit, your answer, albeit the realisation it gave us, also made us realise more about what we don't know. it has lead us, in a way, to even more doubts and questions. but we'd like to thank you for it, since we realise that in this lies the true beauty of science. thank you.

We are ashamed to admit that we haven't read your blog on entanglement as of yet. but we shall surely read it as soon as possible, and hope that when we do so, you won't mind the doubts and questions we might come to ask.

and also sir, we wished to ask you a doubt on matters a bit away from the current topic. we hope you wouldn't mind them. we wished to know sir, for starters, how the universe came into being. and also what your views are on the parallel universe theory. we hope to hear from you soon on the matter. we hope we do not annoy you with our stupid questions.
thank you
A.B.G.D.

hello sir,
i also had another doubt i had forgotten to ask. virtual particles too obey the uncertainty principle. so how come they get to go faster than light while electrons can't. i hope i am no wrong in assuming that vps travel faster than light. but it sure seems reasonable as a charged black hole influences other charged matter outside it. and this could only be possible if the virtual photon moves at a speed greater than that of light. this problem puzzles me greatly. i await your reply.
thank you
A.B.G.D.

Wes D. Sturdevant's picture
Wow! I'm just about to read "Einstein's General and Special Relativity Theory" a second time and glad I have read this, will give me new perspective on what he had to say.  I know Einstein is a bit out dated but some still holds true and thought that would be a good place to start with physics and then told to read "The Quark And The Jaguar" which was recommended by a friend that's a physics major to begin learning about quantum theory... maybe after awhile I'll understand more of this, some of it seems like simple concepts that make plenty of sense, other bits are beyond me without more reading.  But I must say this was a great read including much of the comments and just out of curiousity I have a stupid question about quantum physics I'm told is being more about 'waves' and what 'waves' are exactly instead seeing things on a physical electrons and such level as we do in Newtonian Physics seeing everything as mass around us.  Is my friend wrong or bad at explaining this or are 'waves' a big part of for example the parallel universe theory?  An Explanation for a newbie would be greatly appreciated on this even though I'm sure this is kinda a dumb question but always told there was no dumb questions only questions you don't know the answer to yet. thanks Wes D. Sturdevant

Johannes Koelman's picture
Hi Wes -- the question on quantum physics and the wave nature of particles (and vice versa) is too broad to answer here. A good book to get an appreciation of the strange behavior of the quantum world is 'QED' by Richard Feynman.

You might also like this blog (highlights the utter weirdness of quantum physics).


There is nothing wrong with E=Mc^2. However, this is not an empirical work of Einstein. It's a result of his intuition only.

Amateur Astronomer's picture

Wes,


I second the recommendation of QED by Richard Feynman.


Anirudh,


Einstein derived E=mc^2 from published data of experiments about Doppler shifts on high speed trains and a few other things. It is an exact mathematical calculation that is necessary to make sense of the data. The complete derivation of it was taught in the schools I attended a long time ago. Energy of creating particle pairs came later and has been offered as an independent confirmation.


In his early career Einstein acknowledged that his equation is not valid at very high speeds, but he didn’t know how to fix it. Paul Dirac fixed it in a way that was acceptable to Einstein, and the triangle Johannes showed is derived from the work of Dirac.


If you really look closely at the triangle, it seems like a high speed object has less than the total energy that was put into it. From that comes the ideas about increase of mass at high speeds. That works fine if mass is considered to be the ratio between force and acceleration.


The difficulty occurs if the relativistic mass is creating a large gravitational field. That apparently doesn’t happen, because accelerators have driven particles to such high energies that the additional gravity would have been detected in the particle beam.


The calculation of total energy has been verified by many experiments, but the explanation of it is not entirely satisfactory. One possibility is that the energy difference goes to modify space temporarily and reversibly at very high speeds. There are a lot of published theories about that.


You are correct about Einstein’s equation as long as the particle is not moving quickly, and the intuition you mentioned is accounting for Einstein’s ability to make the calculations for the first time. Actually he got a lot of help from his friends.



EricFD's picture
Wes,

I highly recommend QED by Richard Feynman as well. It's one of the best books written for the layperson that I've ever read. You will learn a lot. For example, did you know that photons travel the path of least time, and this is how mirages are created? You'll learn all kinds of cool stuff like that! ;-)

Anirudh,

I had to rewrite what I had written because I hadn't seen what Jerry had written prior to writing what I had written, and he's right of the money in what he wrote. ;-)

He did have a lot of help. And his very brilliant wife really did used to check his equations! LOL

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